Do \(\left\{{}\begin{matrix}\left(x+1\right)^2\ge0\forall x\\\left(x+2\right)^4\ge0\forall x\\\left(x+3\right)^6\ge0\forall x\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x+1=0\\x+2=0\\x+3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=-1\\x=-2\\x=-3\end{matrix}\right.\)(vô lý)
Vậy \(S=\varnothing\)
Tìm x,y biết :
|x-4|+|6-x|=0
|x+1|-|x-2|=0
|x+2|-|x-3|=0
|x-2|-|x-3|=0
|2x-1|-|x+1|=0
4x-6+2x=12
Tìm x: a)x*x+2*x-3=0 c)x*x+x+1=0 e)x*x-4*x+4=0
b)2*x*x+3*x+1=0 d)x*x-x-6=0
2. tìm x biết
1/2+3/4x+1/4
5/6+1/6:x=-2
x*(x-2/3)=0
1) tìm số nguyên x để 4x-6/ 2x+1
2) Tìm x thuộc z để: 3.(x - 3).(x + 5)< 0
3 tìm x
1/3-(2/3-x + 5/4= 7/12 -(5/2 - 13/6)
bài 6:Tìm x, biết:A,1/4x-1/3=-5/9;B,3,5-Ix-1/2I=0,75;C,x-1/x-5=6/7;D,(x-4)mũ 2=25;E,2 mũ x+2 mũ x-4=272;F,(x+1/2)(2/3-2x)=0
Bài 1: Tìm x biết
1) |5x - 3| = |7 - x|
2) 2 |3 x - 1| - 3x = 7
3) |2x + 3| + 4 = -2x
4) |x + 3/4| - 1/3 = 0
5) 1,6 - |x + 1,5| = 0
6) |x - 1,5| + |2,5 - x| = 0
Tìm x :
a) ( x^2 +1)^3 - (x^4 - x^2 +1 ) . ( x^2 +1 )=0
b) (x - 3 )^3 - (x - 3 ) . ( x^2 + 6x + 9) + 6 .( x+1)^2 + 6x^2 = 33
Tìm x :
a , ( x-1 )( x-4 ) > 0
b , ( x-6 )( x-7 ) < 0
c , ( x-1 )( x-2 ) bé hơn bằng 0
d , ( x-2 )( x- 2/3 ) lớn hơn bằng 0 .
Tìm x
a. ( căn x-6)* ( x - 1) = 0
b. căn x - 1 =3
c. x^3 - 2x = 0
d. x^2 - 4 = 0
e. x^2 - 5 =0
