Question

(x+1/2)+(x+1/4)(+x+1/8)+(x+1/16)=1

Answer 1

\(\left(x+\dfrac{1}{2}\right)+\left(x+\dfrac{1}{4}\right)+\left(x+\dfrac{1}{8}\right)+\left(x+\dfrac{1}{16}\right)=1\)

\(\Leftrightarrow4x-\dfrac{1}{16}=0\)

\(\Leftrightarrow x=\dfrac{1}{64}\)

Answer 2

Hộ e giải bài này vs ạ

 

 

Answer 3

\(\left(x+\dfrac{1}{2}\right)+\left(x+\dfrac{1}{4}\right)+\left(x+\dfrac{1}{8}\right)+\left(x+\dfrac{1}{16}\right)=1\)

\(\Rightarrow4x+\dfrac{15}{16}=1\)

\(\Rightarrow4x=\dfrac{1}{16}\)

\(\Rightarrow x=\dfrac{1}{64}\)

Answer 4

Answer 5

Ta có: \(\left(x+\dfrac{1}{2}\right)+\left(x+\dfrac{1}{4}\right)+\left(x+\dfrac{1}{8}\right)+\left(x+\dfrac{1}{16}\right)=1\)

\(\Leftrightarrow4x+\dfrac{15}{16}=1\)

hay \(x=\dfrac{1}{64}\)