(x+12)*(x-3)=0
=>\(\left[{}\begin{matrix}x+12=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-12\\x=3\end{matrix}\right.\)
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x . (x+7) = 0
(x+12) . (x-3) = 0
(-x + 5 ). ( 3 - x) = 0
(x - 1 ) . ( x +2) . (-3 - 3) = 0
Tìm x :
1) -12 + 3 . ( -x +7 ) = -18
2) x . ( x + 7 ) = 0
3) ( -x + 5 ) . ( 3 - x ) = 0
4) ( x + 12 ) . ( x - 3 ) = 0
5) x . ( 2 + x ) . ( 7 - x ) = 0
6) ( x - 1 ) . ( x + 2 ) . ( -x - 3 ) = 0
Bài 13: Tìm x biết: a) (x-2)(x-3)-D0. b) (x-3)(x-4)-0. c) (x-7)(6-x)=0. d) (x-3)(x-13)=0. The Bài 14: Tìm x biết: a) (12-x)(2-x)=0. b) (x-33)(11-x)=0. c) (21-x)(12-x)=0. d) (50-x)(x-150) =0. Bài 15: Tìm x biết: a) 2x +x = 45. b) 2x +7x = 918. c) 2x+3x 60+5. d) 11x+22x 33.2.
Tìm biết: a) x (x - 6) = 0; b) x (x + 5) = 0; c) (x + 3)(x - 7) = 0; d) (x - 3) ( x 2 + 12) = 0
tìm số nguyên x , biết :
a) x + 546 = 46
b) 2x - 19 x 3 = 27
c) x + 12= 23 + 3 x 3^4
d) x- 12 = 3 - 3 x 2^4
e) ( 27 - x ) nhân ( x +9 ) = 0
f) ( -x) x ( x-43) = 0
1/x.(x+7)=0
2/(x+12).(x-3)=0
3/(-x+5).(3-x)=0
3x - 36=12 . 75 + 25 .12
x:2-12=33 . 40 + 33 . 59 +33
(x-4) . (9-x) = 0
(x-6) . (2020-x)=0
x . (6-x) =0
(x-3-12) . (20-x)=0
Giúp em vs ạ em cảm ơn(◕ᴗ◕✿)
(x+12).(x-3)=0
(-x+5).(3-x)=0
x.(2+x).(7-x)=0
(x-1).(x-2).(-x-3)=0
X : ( - 21 ) =16
X : 12 = -43
( X + 30 ).( X + 3 ) =0
(12 - X ).(X + 3)=0
Giúp mik nhé thanks
Tìm x thuộc Z biết: a) x (x - 7) = 0; b) x (x + 11) = 0; c) (x + 8) (x - 12) = 0; d) (x - 3) ( x 2 + 3) = 0;