Câu hỏi của Khánhh Huyềnn

Question

(x+1)2+(x-2)(x+3)-4x

Nguyễn Lê Phước Thịnh · Accepted Answer

$=x^2-2x+1+x^2+x-6=2x^2-x-5$Câu trả lời: $=x^2-2x+1+x^2+x-6=2x^2-x-5$

ltpc10 · Answer

$\left(x+1\right)^2+\left(x-2\right)\left(x+3\right)-4x$$=x^2+2x+1+\left(x-2\right)\left(x+3\right)-4x$$=x^2+2x+1+x^2+3x-2x-6-4x$$=x^2+1+x^2+3x-6-4x$$=2x^2+1+3x-6-4x$$=2x^2-5+3x-4x$$=2x^2-5-x$$=2x^2-x-5$Câu trả lời: $\left(x+1\right)^2+\left(x-2\right)\left(x+3\right)-4x$$=x^2+2x+1+\left(x-2\right)\left(x+3\right)-4x$$=x^2+2x+1+x^2+3x-2x-6-4x$$=x^2+1+x^2+3x-6-4x$$=2x^2+1+3x-6-4x$$=2x^2-5+3x-4x$$=2x^2-5-x$$=2x^2-x-5$

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