\(x+\dfrac{x}{2}=\dfrac{3}{4}\)
\(\dfrac{2x}{2}+\dfrac{x}{2}=\dfrac{3}{4}\)
\(\dfrac{3x}{2}=\dfrac{3}{4}\)
\(3x.4=2.3\)
\(12x=6\)
\(x=\dfrac{1}{2}\)
\(x+x\times\dfrac{1}{2}=\dfrac{3}{4}\)
\(x\times\left(1+\dfrac{1}{2}\right)=\dfrac{3}{4}\)
\(x\) \(\times\) \(\dfrac{3}{2}\) \(=\) \(\dfrac{3}{4}\)
\(x\) \(=\dfrac{3}{4}:\dfrac{3}{2}\)
\(x\) \(=\dfrac{1}{2}\)
Ta có: \(x+x\cdot\dfrac{1}{2}=\dfrac{3}{4}\)
\(\Leftrightarrow x\cdot\dfrac{3}{2}=\dfrac{3}{4}\)
hay \(x=\dfrac{1}{2}\)
