\(x-\left(\dfrac{50x}{100}+\dfrac{25x}{100}\right)=11\dfrac{1}{4}\)
\(x-\dfrac{3x}{4}=\dfrac{45}{4}\)
\(\dfrac{x}{4}=\dfrac{45}{4}\Rightarrow x=45\)
Ta có: \(x-\left(\dfrac{50x}{100}+\dfrac{25x}{200}\right)=11\dfrac{1}{4}\)
\(\Leftrightarrow x-\dfrac{1}{2}x-\dfrac{1}{8}x=\dfrac{45}{4}\)
\(\Leftrightarrow x\cdot\dfrac{3}{8}=\dfrac{45}{4}\)
hay x=30