Ta có : \(x=\left(3.2\right)+\dfrac{68}{5}=\dfrac{98}{5}\)
Vậy ...
Ta có: \(x-\dfrac{68}{5}=3.2\)
\(\Leftrightarrow x=\dfrac{16}{5}+\dfrac{68}{5}\)
hay \(x=\dfrac{84}{5}\)
Vậy: \(x=\dfrac{84}{5}\)
\(x-\dfrac{68}{5}=3.2\)
\(x-\dfrac{68}{5}=6\)
\(x=6+\dfrac{68}{5}\)
\(x=\dfrac{98}{5}\)