\(x-7\sqrt{x}+6\)
\(=x-\sqrt{x}-6\sqrt{x}+6\)
\(=\sqrt{x}\left(\sqrt{x}-1\right)-6\left(\sqrt{x}-1\right)\)
\(=\left(\sqrt{x}-6\right)\left(\sqrt{x}-1\right)\)
Đề bài là gì vậy bạn ?
Chứng minh rằng với mọi số thực x,y,z luôn có:
\(\left(x+y+z\right)^6+\left(y+z-x\right)^6+\left(z+x-y\right)^6+\left(x+y-z\right)^6\le244\left(x^6+y^6+z^6\right)\)
So sánh
a) (156 + 78) x 6 .............156 x 6 + 79 x 6
b) (1923 - 172) x 8.............1923 x 8 - 173 x 8
c) (236 - 54) x 7................237 x 7 - 54 x 7
Tìm x
a)X x 6 = 3048 : 2
b) 56 : X = 1326 – 1318
rút gọn
A=[3/2 -(x2+2)/(x2+1)*(x+1)*(x-4)/x6-1)*(x+6)]/(x+3)*(x+26)/3*(x+6)*(x-2)
(\(\frac{x+6}{x-6}\))(\(\frac{x+4}{x-4}\))2 +(\(\left(\frac{x-6}{x+6}\right)\left(\frac{x+9}{x-9}\right)^2\)=\(2.\frac{x^2+36}{x^2-36}\)
giải phương trình
2 x^3+9 x^2-6 x (1+2 sqrt(6 x-1))+2 sqrt(6 x-1)+8 = 0
Giải hệ phương trình: \(\hept{\begin{cases}2.x^{2004}=y^6+z^6\\2.y^{2004}=z^6+x^6\\2.z^{2004}=x^6+y^6\end{cases}}\)
Tìm `ĐKXĐ`:
\(\sqrt{\dfrac{-5}{6+x}}\)
\(\sqrt{\dfrac{-2}{6-x}}\)
\(\sqrt{\dfrac{-x+3}{-6}}\)
\(\sqrt{\dfrac{7x-1}{-9}}\)
\(\sqrt{\dfrac{x+2}{x^2+2x+1}}\)
\(\sqrt{\dfrac{x-2}{x^2-2x+4}}\)
((6*x^2 +8*x + 7)/(x^3 -1) + x/(x^2 +x+1) + 6 /(1 -x)) * (x^2 -1)
căn(x+3) + căn(6-x) - căn(x+3)6-x)) = 3
