\(\left(x-5\right)\left(x+5\right)-\left(x+1\right)\left(x+4\right)=x^2-25-x^2-5x-4=-5x-29\)
\(\left(x-5\right)\left(x+5\right)-\left(x+1\right)\left(x+4\right)\)
\(=x^2-25-x^2-5x-4\)
=-5x-29
\(\left(x-5\right)\left(x+5\right)-\left(x+1\right)\left(x+4\right)=x^2-25-x^2-5x-4=-5x-29\)
\(\left(x-5\right)\left(x+5\right)-\left(x+1\right)\left(x+4\right)\)
\(=x^2-25-x^2-5x-4\)
=-5x-29
Bài1:Rút gọn
a,(4x-5)(3x+2)-(7-3x)(x+2)
b,(-2x+1)(x-5)-3(x-2)(x+1)
c,(x^2-7)(x-5)+(3x^2+5)(2x-4)
d,(x^2+3x-2)(x+4)-4x(x-5)
Bài2:Tìm xbiết
a,(x-4)(x+3)-(x+1)(x-5)=8
b,(3x-2)(x+1)-3x(x+7)=13
c,(x+5)(x-5)-x(x+2)=9
d,(x-1)(x^2+x+1)-x(x^2-3)=1
1) (3x-2)/3-2=(4x+1)/42) (x-3)/4+(2x-1)/3=(2-x)/63) 1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)4) (x+4)/5-x+4=x/3-(x-2)/25) (4-5x)/6=2(-x+1)/2 6) (-(x-3))/2-2=5(x+2)/4 7)2(2x+1)/5-(6+x)/3=(5-4x)/158) (7-3x)/2-(5+x)/5=1 9)(x-1)/2+3(x+1)/8=(11-5x)/310)(3+5x)/5-3=(9x-3)/4
a,x+5/x-1+8/x^2-4x+3=x+1/x-3 b,x-4/x-1-x^2+3/1-x^2+5/x+1=0 c,3x/4-5=3-x/2+5x-1/6 d,(x-2)(x+2)-(x-3)(x+4)-2x+3=0 e,(x-1)^2+2(x+1)=5x+5 g,(x-3)(x+4)x=0
- Bài 12: Thực hiện phép tính
1) x(1 - x) + (x - 1) ^ 2 3) (x + 2) ^ 2 - (x - 3)(x + 1)
5) (x - 2) ^ 2 + (x - 1)(x + 5)
7) (1 - 2x)(5 - 3x) + (4 - x) ^ 2
9) (x + 1) ^ 2 + (x - 2)(x + 2) - 4x
11) (x + 4) ^ 2 + (x + 5)(x - 5) - 2x(x + 1)
13) (x - 1) ^ 2 - 2(x + 3)(x - 3) + 4x(x - 4)
2) (x - 3) ^ 2 - x ^ 2 + 10x - 7
4) (x + 4)(x - 2) - (x - 3) ^ 2
6) (x + 3)(x - 3) - x(23 + x)
8) (x - 2)(x + 2) - (x - 3)(x + 1)
10) (x + 2) ^ 2 - (x + 3)(x - 3) + 10
12) (x - 1) ^ 2 - (x - 4)(x + 4) + (x + 3) ^ 2
14) (y - 3)(y + 3)(y ^ 2 + 9) -(y^ 2 +2)(y
giải các phương trình sau
1/ ( x-2)(x-5)=(x-3)(x-4)
2/ (x-7)(x+7) +x^2 -2=2(x^2+5)
3/ (x-1)^2 +(x+3)^2 =2(x-2)(x=2)
4/ (x+1)^2= (x+3)(x-2)
5/ x^2-(2x-1)(x+3)= 3-x(5+x)
6/ 3(5-2x) -4( x+2) =5x-18
Câu 6. Tìm giá trị x thỏa mãn 5(2x – 4) = x(2x – 4)
A. x = 4, x = 5
B. x = 2 ,x = 5
C. x = -4, x = -5
D. x = -2, x = -5
Câu 7. Phân tích đa thức 5x2– 10x + 5 thành nhân tử ta được
A. 5(x-1)2
B. 5(x+1)2
C. 5(x2-10x+1)
D. 5(x2+10x+1)
Câu 8 .Thực hiện phép tính (x + 3)(x2− 3x + 9) - (x3 − 27) ta được kết quả
A. 0
B. 27
C. 36
D. 54
Tìm x, biết :
a) (x-2)3 +6(x+1)2-x3+12=0
b) (x-5) (x+5) - (x+3)2+3(x-2)2=(x+1)2- (x+4)(x-4)+3x2
c) (2x+3)2 +(x-1)(x+1)=5(x+2)2-(x-5)(x+1)+(x+4)
d) (1-3x)2-(x-2)(9x+1)=(3x-4)(3x+4)-9(x+3)2
Giúp mk với ạ, mk cảm ơn !
Rút gọn
a) (x+2) .( x+3) - (x-2) .(x+5)
b) (8-5x).(x+2)+4(x-2).(x+1)+2.(x-2).(x+2)+10
c) 4.(x-1).(x+5)-(x+2)(x+5)-3.(x-1).(x+2)
d) (x-1).(x^5 + x^4 + x^3 + x^2 + x + 1)
tim x
1) 4x(x-5)-(x-1)(4x-3)=5
2) (x-5)(x-4)-(x+1)(x-2)=7
3) (x-5)(-x+4)-(x-1)(x+3)=-2x2
Tìm x:
a, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
b, 2x2+3(x-1)(x+1)=5x(x+1)
c, (8-5x)(x+2)+4(x-2)(x+1)+2(x-2)(x+2)=0
d, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)