\((x-5)^3+4=129\\\Rightarrow (x-5)^3=129-4\\\Rightarrow (x-5)^3=125\\\Rightarrow (x-5)^3=5^3\\\Rightarrow x-5=5\\\Rightarrow x=5+5\\\Rightarrow x=10\\Vậy:x=10\)
(x-53)+4=129
⇒x-53=129-4
⇒x-53=125
⇒x-125=125
⇒x=250
129 -5[29-(6-1) ^2]
=129 - 5[29- 5^2]
= 129 -5[ 29-25]
=129 - 5 × 4
=129 - 20
=109