Question

(x-3) mũ 49-x+3=0

Answer 1

\(\Leftrightarrow\left(x-3\right)\left[\left(x-3\right)^{48}-1\right]=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-3=1\\x-3=-1\end{matrix}\right.\Leftrightarrow x\in\left\{2;3;4\right\}\)

Answer 2

⇔(x−3)[(x−3)48−1]=0⇔(x−3)[(x−3)48−1]=0

⇔⎡⎢⎣x−3=0x−3=1x−3=−1⇔x∈{2;3;4}⇔[x−3=0x−3=1x−3=−1⇔x∈{2;3;4}