\(\Leftrightarrow x-\dfrac{2}{5}=-\dfrac{6}{10}\)
\(\Leftrightarrow x=-\dfrac{6}{10}+\dfrac{2}{5}\)
\(\Leftrightarrow x=-\dfrac{1}{5}\)
Vậy \(x=-\dfrac{1}{5}\)
Ta có: \(x-\dfrac{2}{5}=-\dfrac{6}{10}\)
\(\Leftrightarrow x=\dfrac{-3}{5}+\dfrac{2}{5}=\dfrac{-1}{5}\)