=>4x-8=3x+3
=>4x-3x=8+3
=>x=11
\(\dfrac{4\left(x-2\right)}{12}=\dfrac{3\left(x+1\right)}{12}\\ 4x-8-3x-3=0\\ x-11=0\\ x=11\)
\(\dfrac{x-2}{3}=\dfrac{x+1}{4}\)
\(\Leftrightarrow\dfrac{x-2}{3}-\dfrac{x+1}{4}=0\)
\(\Leftrightarrow\dfrac{4\left(x-2\right)-3\left(x+1\right)}{12}=0\)
\(\Leftrightarrow4x-8-3x-3=0\)
\(\Leftrightarrow x-11=0\)
\(\Leftrightarrow x=11\)