\(\left(x-2\right)^2=1\)
TH1 : x - 2 = 1 <=> x = 3
TH2 : x - 2 = -1 <=> x = 1
Ta có: \(\left(X-2\right)^2=1\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)
(x-2)2=12
=> \(\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)
(x - 2)2 = 1
<=> (x - 2)2 - 1 = 0
<=> (x - 2 - 1)(x - 2 + 1) = 0
<=> (x - 3)(x - 1) = 0
<=> \(\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)