\(\Leftrightarrow\left(x-1\right)\left(x+1\right)+x=2x+1\)
\(\Leftrightarrow x^2+x-1=2x+1\)
\(\Leftrightarrow x^2-x-2=0\)
=>(x-2)(x+1)=0
=>x=2(nhận) hoặc x=-1(loại)
\(\Leftrightarrow\left(x-1\right)\left(x+1\right)+x=2x+1\)
\(\Leftrightarrow x^2+x-1=2x+1\)
\(\Leftrightarrow x^2-x-2=0\)
=>(x-2)(x+1)=0
=>x=2(nhận) hoặc x=-1(loại)
Giải phương trình sau
C x-2/c+2+3/x-2=x^2-11/x^2-4
D 2/x+1-1/x-2=3x-11/(x+1)(x-2)
E x+3/x-2-1/x=2/x^2+2x
F x+2/x-2-1/x=2/x(x-2)
G 3x-1/x-1-2x+5/x-3=1
H 2x/2x-1+x/2x+1=1+4/(2x-1)(2x+1)
thực hiện phép tính
a, 2x-1/2x+1 :(2x-1+2-4x/2x+1)
b,(1/1-x -1) : (x- 1-2x/1-x +1)
c,(1/x + x-2/x^2 -4 -2+x/x^2+2x):(x^2+2x+1)/x^2
d,{1/x^2 + 1/y^2 + 2/ x+y.(1/x + 1/y )} : x^3+y^3/x^2+y^2
1.giải phương trình :
1)1 + 2/x-1 + 1/x+3=x^2+2x-7/x^2+2x-3
2)x/x^2+5x+6=2/x^2+3x+2 (x=3)
3)1/x^2+9x+20 - 1/x^2+8x+12=x^2-2x-33/x^2+8x+15 (x=-5,7)
4)x+5/3x-6 - 1/2=2x-3/2x-4 (x=25/7)
5)x-1/x^3+1 + 2x+3/x^2-x+1=2x+4/x+1 - 2(x=0)
giải phương trình:
a, 1+2x-5/6=3-x/4
b, x+3/x+1+x-2/x=2
c, x-2/x+2+3/x-2=x^2-11/x^2-4
d,2/x+1-1/x-2=3x-11/x+1*x-2
e,x+2/x-2-1/x=2/x^2-2x
f, x+2/x-2-1/x=2/x*(x-2)
g,3x-1/x-1=2x+5/x-3
h,2x/2x-1+x/2x+1=1+4/2x-1*2x+1
mình cần bài này gấp ạ
Quy đồng mẫu các phân thức:
1) 7x-1/2x^2+6x; 3-2x/x^2-9
2) 2x-1/x-x^2; x+1/2-4x+2x^2
3) x-1/x^3+1; 2x/x^2-x+1; 2/x+1
4) 7/5x; 4/x-2y; x-y/8y^2-2x^2
5) x/x^3-1; x+1/x^2-x; x-1/x^2+x+1
6) x/x^2-2ax+a^2; x+a/x^2-ax
Giải phương trình:
A) 1-x/x+1 +3 = 2x+3/x+1
B) (x+2)^2/2x-3 -1 = x^2-10/2x-3
C) 5x-2/2-2x + 2x-1/2 = 1 + x^2+x-3/x-1
D) 5-2x/3 - (x-1)(x+1)/1-3x = (x+2)(1-3x)/9x-3
E) x-3/x-2 + x-2/x-4 = -1
F) 1 + x/3-x = 5/(x+2)(3-x) + 2/x+2
G) x+1/x-1 - x-1/x+1 = 3x( 1 - x-1/x+1 )
H) 1-6x/x-2 + 9x-4/x+2 = x(3x-2)+1/x^2-4
I) 3x-1/x-1 - 2x+5/x+3 + 4/x^2+2x-3 = 1
Thực hiện phép tính:
a) (1/x+x-2) : (1/x^2-x+1-3/x-1)
b) [x^2-2x+1/3x+(x+1)^2 - 1-2x^2+4x/x^3-1 + 1/x-1] : 2x/x^3+x
a) 2(7x+10)+5=3(2x-3)-9x
b) (x+1)(2x-30=(2x-10)(x+5)
c) 2x+x(x+1)(x-1)=(x+1)(x2-x+1)
d) (x-1)3-x(x+1)2=5x(2-x)-11(x+2)
Giải các phương trình sau bằng cách đưa về dạng ax + b = 0 :
1. a) 5 - (x - 6) = 4(3 - 2x)
b) 2x(x + 2)^2 - 8x^2 = 2(x - 2)( x^2 + 2x + 4)
c) 7 - (2x + 4) = - (x + 4)
d) (x - 2)^3 + (3x - 1)(3x + 1) = (x + 1)^3
e) (x + 1)(2x - 3) = (2x - 1)(x + 5)
f) (x - 1)^3 - x(x + 1)^2 = 5x(2 - x ) - 11(x +2)
g) (x-1) - (2x - 1 ) = 9 - x
h) (x-3)(x+4) - 2(3x - 2) = (x-4)^2
i) x(x+3)^2 - 3x = (x + 2)^3 + 1
j) (x + 1)(x^2 - x + 1) - 2x = x(x + 1)(x-1)
Khai triển và thu gọn:
1, x(3x - 1) - 2x(x - 1) - (x - 2)2
2, x(2 + x) - (x - 1)(3 - x)-(3 - x)2
3, (2x - 1)2 - 2(2x - 1)(2x - 3) + (3 - 2x)2