\(\Leftrightarrow\left(x+\dfrac{1}{7}\right)^3=63+1=64\)
=>x+1/7=4
hay x=27/7
( x + 1/7 ) 3 - 1 = 63
=> ( x + 1/7 ) 3 = 63 + 1 = 64 = 43
=> x + 1/7 = 4
=> x = 4 - 1/7
=> x = \(\dfrac{27}{7}\)
(x+1/7)3-1=63
(x+1/7)3 =63+1=64=43
=>x+1/7 =4
x =4-1/7=28/7-1/7=27/7