\(x-\frac{1}{4}=\frac{-4}{1-x}\)
\(\Leftrightarrow\frac{4x^2}{4x}-\frac{x}{4x}=\frac{-4}{1-x}\)
\(\Leftrightarrow\frac{4x^2-x}{4x}=\frac{-4}{1-x}\)
\(\Leftrightarrow\left(4x^2-x\right).\left(1-x\right)==-4x.4\)
\(\Leftrightarrow\left(4x^2-1\right)-\left(4x^3-x^2\right)=-16x\)
\(\Leftrightarrow4x^2-1-4x^3+x^2+16x=0\)
Chịu