\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=0\\2x-\dfrac{3}{4}=0\end{matrix}\right.\Leftrightarrow x\in\left\{-\dfrac{1}{3};\dfrac{3}{8}\right\}\)
1) (x + 1/2).(2/3 - 2x) = 0 2) 2/3x + 1/2x = 5/2 : 3 và 3/4 3) (2x - 3)(6 - 2x)= 0 4) -5(x + 1/5) - 1/2(x - 2/3) = 3/2x - 5/6
Tìm x biết
a,3/1/2x -5=0
b,3×(x-2)+5/3/4=0
c,1/2x-3-2=0
d, 1/3x+1=2x-3/2
e,(x)-3=5/1/2
g,(x-5)(x+1/2)=0
H,(2x-1/2)=4
i,(4+x3)=8
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Tìm x
(2x-7)+17=6
12-2.(3-3x)=-2
-14+3.(-x+5)=-20
-90:5.(-3-2x)=6
(x+1).(x-3)=0
(2x-2).(x+4)=0
(22+4).(x+3)=0
(5-x).(6-2x)=0
3.(x+1)+5=x+8
-4.(2x+9)-(-8x+3)-(x+13)=0
a 3(x+1)-2(3x-4)=-13
b 2(x-3)-4(2x-1)=-20
c 2x(x+3)=0
d (x-1)(5x-x)=0
e (x+3)^2(4-x)=0
tìm x , biết :
a, (x-1/5).(x-1+3/5)<0
b,(x-4/7):(x+1/2)>0
c,(2x-3):(x+1+3/4)
d,|2x-1|+1=2x
1,x=3x2
2,(x+5)(x-3)-(x-30)=0
3,(2x-6)(x+4)+2(2x-6)=0
4,(2x-5)(x+9)+6x-15=0
3,(2x-5)(x+6)+8x-20=0
Tìm x
a) 1/3x + 2/5( x - 1 ) = 0
b) (2x - 3 )(6 - 2x ) =0
c) 2|1/2x - 1/3 | - 3/2 = 1/4
d) 3/4 - 2 . | 2x - 2/3 | = 2
e) ( 3x - 1)(-1/2x + 5 ) = 0
g)-5(x + 1/5 ) - 1/2(x - 2/3 ) = 2/3x - 5/6
h) 3(x - 1/2 ) - 5(x + 3/5 ) = -3 + 1/5
i) 60%x + 2/3x = 1/3. 6và1/3 ( 6và1/3 là hỗn số )
Tìm x
1)7.(x-1) +2x.(x-1) =0
2)2x.(x-3)+9x-27=0
3)4.(x-1/2)+4.(5-x)=9/2
