(x-128+20):192 = 0
=> x - 128 + 20 = 0
=> x - 128 = -20
=> x = -20 + 128
=> x = 108
Vậy x = 108
\(\left(x-128+20\right):192=0\)
\(x-\left(128-20\right)=0\cdot192\)
\(x-108=0\)
\(x=0+108\)
\(x=108\)
\(\left(x-128+20\right):192=0\)
\(\left(x-128+20\right)=0\times192\)
\(\left(x-128+20\right)=0\)
\(x-128=0-20\)
\(x-128=-20\)
\(x=\left(-20\right)+128\)
\(x=108\)
hok tốt
(x-128+20):192=0
(x-148) : 192 = 0
x - 140 = 0
x = 0 +148
x = 148
Học tốt
^^
[ x- 148 ] : 192 = 0
x - 148 = 0
x = 0 + 148
x = 148
k mình nếu đúng nha !
(x-128+20):192=0
x-128+20 =0
x-128 =0-20
x-128 =-20
x =-20+128
x =108
Vậy x=108