Question

(x-1)^26+(3+x)^22=0

Answer 1

Vì: \(\left(x-1\right)^{26}\ge0\forall x\)

\(\left(3+x\right)^{22}\ge0\forall x\)

=>\(\left(x-1\right)^{26}+\left(3+x\right)^{22}\ge0\forall x\)

Mà: \(\left(x-1\right)^{26}+\left(3+x\right)^{22}=0\)

\(\Rightarrow\orbr{\begin{cases}\left(x-1\right)^{26}=0\\\left(3+x\right)^{22}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}\Rightarrow}}\) ko cs giá trị thỏa mãn

=.= hok tốt!!