Question

|x-1/2|=3-2x

Answer 1

\(\left|x-\dfrac{1}{2}\right|=3-2x\)

* để \(\left|x-\dfrac{1}{2}\right|=x-\dfrac{1}{2}< =>x-\dfrac{1}{2}\ge0< =>x\ge\dfrac{1}{2}\)

\(=>x-\dfrac{1}{2}=3-2x< =>3x=\dfrac{7}{2}< =>x=\dfrac{7}{6}\left(TM\right)\)

*để \(\left|x-\dfrac{1}{2}\right|=\dfrac{1}{2}-x< =>x-\dfrac{1}{2}< 0< =>x< \dfrac{1}{2}\)

\(=>\dfrac{1}{2}-x=3-2x< =>x=3-\dfrac{1}{2}=2,5\left(loai\right)\)

vậy \(x=\dfrac{7}{6}\)

Answer 2

\(\left|x-\dfrac{1}{2}\right|=3-2x\)

\(x-\dfrac{1}{2}=3-2x\)

\(x+2x=3+\dfrac{1}{2}\) 

\(3x=\dfrac{7}{2}\) 

x = \(\dfrac{7}{6}\)

Vậy x = \(\dfrac{7}{6}\)​​