\(GS:n_{SO_2}=n_{O_2}=1\left(mol\right)\)
\(SO_2+\dfrac{1}{2}O_2\underrightarrow{^{^{t^0,V_2O_5}}}SO_3\)
Bđ: \(1..........1\)
Pư: \(2a.....a.........2a\)
Kt: \(1-2a...1-a.....2a\)
\(n_{hh}=1-2a+1-a+2a=2-a\left(mol\right)\)
\(\%SO_3=\dfrac{2a}{2-a}\cdot100\%=35.3\%\)
\(\Rightarrow a=0.3\)
\(H\%=\dfrac{0.3\cdot2}{1}\cdot100\%=60\%\)