\(=-19-40+19+\left(-3\right)\cdot\left(-8\right)\)
\(=-40+24=-16\)
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Các câu hỏi tương tự
Tính
\(\left(-19\right)+5+\left(-8\right)+19+\left(-3\right).\left(-2\right)^3\)
Cái vừa nẫy hơi sai đề mk đăng lại
Tính
\(\frac{\left(1+17\right).\left(1+\frac{17}{2}\right).\left(1+\frac{17}{3}\right)....\left(1+\frac{17}{19}\right)}{\left(1+19\right).\left(1+\frac{19}{2}\right).\left(1+\frac{19}{3}\right)....\left(1+\frac{19}{17}\right)}\)
Tính giá trị biểu thức: A=\(\frac{\left(1+17\right).\left(1+\frac{17}{2}\right).\left(1+\frac{17}{3}\right)....\left(1+\frac{17}{19}\right)}{\left(1+19\right).\left(1+\frac{19}{2}\right).\left(1+\frac{19}{3}\right)...\left(1+\frac{19}{17}\right).}\)
Tính giá trị biểu thức: A=\(\frac{\left(1+17\right)\times\left(1+\frac{17}{2}\right)\times\left(1+\frac{17}{3}\right)....\left(1+\frac{17}{19}\right)}{\left(1+19\right)\times\left(1+\frac{19}{2}\right)\times\left(1+\frac{19}{3}\right)....\left(1+\frac{19}{17}\right)}\)
Tính:
\(A=\frac{\left(1+17\right)\left(1+\frac{17}{2}\right)\left(1+\frac{17}{3}\right)...\left(1+\frac{17}{19}\right)}{\left(1+19\right)\left(1+\frac{19}{2}\right)\left(1+\frac{19}{3}\right)...\left(1+\frac{19}{17}\right)}\)
bài 2: 1, \(\left(\dfrac{5}{6}\right)^{10}.\left(\dfrac{3}{10}\right)^{10}\)2,\(\left(\dfrac{4}{7}\right)^{19}:\left(\dfrac{-12}{35}\right)^{19}\) 3,\(\left(\dfrac{-3}{7}\right)^7:\left(\dfrac{-3}{5}\right)\)
1.Tính
\(A=\frac{\left(1+17\right)\left(1+\frac{17}{2}\right)\left(1+\frac{17}{3}\right)+...+\left(1+\frac{17}{19}\right)}{\left(1+19\right)\left(1+\frac{19}{2}\right)\left(1+\frac{19}{3}\right)+...+\left(1+\frac{19}{17}\right)}\)
Thánh nào giúp mk với
\(\left(\frac{3}{79}\right)^{20}.\left(\frac{3}{-79}\right)^{19}=\)
\(\left(\frac{2}{3}\right)^5:\left(\frac{2}{-3}\right)^3=\)
\(\left(\frac{-5}{8}\right)^3:\left(\frac{5}{8}\right)^{12}\)
\(\frac{\left(1+17\right)+\left(1+\frac{17}{2}\right)+\left(1+\frac{17}{3}\right)+........+\left(1+\frac{17}{19}\right)}{\left(1+19\right)+\left(1+\frac{19}{2}\right)+\left(1+\frac{19}{3}\right)+........+\left(1+\frac{19}{17}\right)}\)