\(=2\sqrt{3}-3\sqrt{3}+\sqrt{3}-1=-1\)
\(A=2\sqrt{3}-\sqrt{27}+\dfrac{3-\sqrt{3}}{\sqrt{3}}\\ =2\sqrt{3}-3\sqrt{3}+\left(\sqrt{3}-1\right)\\ =-\sqrt{3}+\sqrt{3}-1\\ =-1\)
\(=2\sqrt{3}-3\sqrt{3}+\sqrt{3}-1=-1\)
\(A=2\sqrt{3}-\sqrt{27}+\dfrac{3-\sqrt{3}}{\sqrt{3}}\\ =2\sqrt{3}-3\sqrt{3}+\left(\sqrt{3}-1\right)\\ =-\sqrt{3}+\sqrt{3}-1\\ =-1\)
tính
a) \(\left(\dfrac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-\sqrt{2}}+1\right)\dfrac{1}{2+\sqrt{6}}\)
b) \(\sqrt{27}-6\sqrt{\dfrac{1}{3}}+\dfrac{\sqrt{3}-3}{\sqrt{3}}\)
1) Tính:
\(b,\sqrt{2}.\sqrt{7+3\sqrt{5}}-\dfrac{4}{\sqrt{5-1}}\)
\(c,\sqrt{27}-6\sqrt{\dfrac{1}{3}}+\dfrac{\sqrt{3}-3}{\sqrt{3}}\)
\(d,\dfrac{9-2\sqrt{3}}{3\sqrt{6}-2\sqrt{2}}\)
Giúp mình với, mình cần gấp
Cho \(P=\left(\dfrac{x+3}{x-9}+\dfrac{1}{\sqrt{x}+3}\right):\dfrac{\sqrt{x}}{\sqrt{x}-3}\)
a, Rút gọn P
b, Tính P khi \(x=\sqrt{27+10\sqrt{2}}-\sqrt{18+8\sqrt{2}}\)
a) A=\(\left(\dfrac{2+\sqrt{2}}{\sqrt{2}+1}-\dfrac{\sqrt{15}-\sqrt{35}}{\sqrt{3}-\sqrt{7}}\right).\left(\sqrt{2}+\sqrt{5}\right)\)
b) B=\(\dfrac{12}{3+\sqrt{3}}-\dfrac{6}{\sqrt{3}}+\dfrac{\sqrt{27}-3\sqrt{2}}{\sqrt{3}.\sqrt{2}}\)
c)C=\(\left(\dfrac{1}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}}\right).\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}-\dfrac{\sqrt{x}+2}{\sqrt{x}-1}\right)\)(x>0,x≠1,x≠4)
a)5\(\sqrt{27}\)+3\(\sqrt{48}\)-2\(\sqrt{12}\)-6\(\sqrt{3}\)
b)\(\dfrac{3}{2+\sqrt{3}}\)+\(\dfrac{13}{4-\sqrt{3}}\)+\(\dfrac{6}{\sqrt{3}}\)
a) \(\sqrt{4x^2-9}=2\sqrt{x+3}\)
b) \(\sqrt{4x+20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
c) \(\dfrac{2}{3}\sqrt{9x-9}-\dfrac{1}{4}\sqrt{16x-16}+27\sqrt{\dfrac{x-1}{81}}=4\)
d)\(5\sqrt{\dfrac{9x-27}{25}}-7\sqrt{\dfrac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\dfrac{9x^2-81}{81}}=0\)
Tính
\(\dfrac{2}{3}\sqrt{27}-\dfrac{9}{2}\sqrt{\dfrac{16}{81}}+\sqrt{\left(1-\sqrt{3}\right)^2}\)
Tính giá trị biểu thức:
a) \(P=\left(x^3+12x-9\right)^{2005}\), biết \(x=\sqrt[3]{4\left(\sqrt{5}+1\right)}-\sqrt[3]{4\left(\sqrt{5}-1\right)}\);
b) \(Q=x^3+ax+b\), biết \(x=\sqrt[3]{-\dfrac{b}{2}+\sqrt{\dfrac{b^2}{4}+\dfrac{a^3}{27}}}+\sqrt[3]{-\dfrac{b}{2}-\sqrt{\dfrac{b^2}{4}+\dfrac{a^3}{27}}}\)
Rút gọn : ( giúp với )
a) \(\dfrac{\sqrt{6}+\sqrt{10}}{\sqrt{21}+\sqrt{35}}\)
b) \(\dfrac{\sqrt{405}+3\sqrt{27}}{3\sqrt{3}+\sqrt{45}}\)
c) \(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{4}-\sqrt{6}-\sqrt{9}-\sqrt{12}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
d) \(\dfrac{\sqrt{6-2\sqrt{5}}}{\sqrt{5}-1}\)
\(c,2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}\)
d,\(\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}+\sqrt{\dfrac{2+\sqrt{3}}{2-\sqrt{3}}}\)