Question

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A= \(\frac{3^2}{8.11}\)+ \(\frac{3^2}{11.14}\)+ \(\frac{3^2}{14.17}\)+........+ \(\frac{3^2}{197.200}\)

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Answer 1

A=\(\frac{3.3}{8.11}\)+\(\frac{3.3}{11.14}\)+\(\frac{3.3}{14.17}\)+........+\(\frac{3.3}{197.200}\)

A=3\(\frac{3}{8.11}\)+3\(\frac{3}{11.14}\)+3\(\frac{3}{14.17}\)+............+3\(\frac{3}{197.200}\)

A=3.(\(\frac{3}{8.11}\)+\(\frac{3}{11.14}\)+\(\frac{3}{14.17}\)+..............+\(\frac{3}{197.200}\))

A=3.(\(\frac{1}{8}\)-\(\frac{1}{11}\)+\(\frac{1}{11}\)-\(\frac{1}{14}\)+\(\frac{1}{14}\)-\(\frac{1}{17}\)+.........+\(\frac{1}{197}\)-\(\frac{1}{200}\))

A=3.(\(\frac{1}{8}\)-\(\frac{1}{200}\))

A=3.(\(\frac{50}{400}\)-\(\frac{2}{200}\))

A=3.\(\frac{48}{400}\)

A=3.\(\frac{3}{25}\)

A=\(\frac{9}{25}\)