=\(\dfrac{10}{3}-\left(\dfrac{22}{5}+\dfrac{4}{3}\right)\)
=\(\dfrac{10}{3}-\dfrac{86}{15}\)
=\(-\dfrac{12}{5}\)
Ta có: \(3\dfrac{1}{3}-\left(4\dfrac{2}{5}+1\dfrac{1}{3}\right)\)
\(=\dfrac{10}{3}-\dfrac{22}{5}-\dfrac{4}{3}\)
\(=2-\dfrac{22}{5}=-\dfrac{12}{5}\)
= 10/9 -( 22/5+4/3)
=10/9 - (66/15+20/15)
=10/9 - 86/15
=50/45 - 258/15
= -203/15