Question

tính:

Answer 1

a: \(=12+\dfrac{1}{3}-7-\dfrac{6}{4}=5+\dfrac{1}{3}-\dfrac{3}{2}\)

\(=\dfrac{30}{6}+\dfrac{2}{6}-\dfrac{9}{6}=\dfrac{23}{6}\)

b: \(=\dfrac{23}{6}+\dfrac{13}{6}\cdot6=\dfrac{23}{6}+13=\dfrac{23+78}{6}=\dfrac{101}{6}\)

c: \(=3+\dfrac{1}{2}+4+\dfrac{5}{7}-5-\dfrac{5}{14}\)

\(=2+\dfrac{7+10-5}{14}=2+\dfrac{12}{14}=2+\dfrac{6}{7}=\dfrac{20}{7}\)

d: \(=\dfrac{9}{2}+\dfrac{1}{2}:\dfrac{11}{2}=\dfrac{9}{2}+\dfrac{1}{11}=\dfrac{99+2}{22}=\dfrac{101}{22}\)

e: \(=\dfrac{6}{7}:\dfrac{3}{8}-\dfrac{5}{8}=\dfrac{6}{7}\cdot\dfrac{8}{3}-\dfrac{5}{8}=\dfrac{16}{7}-\dfrac{5}{8}\)

\(=\dfrac{128}{56}-\dfrac{35}{56}=\dfrac{93}{56}\)

f: \(=34-2:\dfrac{1}{10}=34-20=14\)