Bài 1:
a: \(\left(-0,25\right)^7\cdot4^3=\left(-\frac14\right)^7\cdot4^3=-\frac{1}{4^7}\cdot4^3=-\frac{1}{4^4}=-\frac{1}{256}\)
b: \(\left(\frac35-\frac{7}{20}+\frac14\right)\cdot\left(\frac53\right)^2\)
\(=\left(\frac{12}{20}-\frac{7}{20}+\frac{5}{20}\right)\cdot\frac{25}{9}=\frac{10}{20}\cdot\frac{25}{9}=\frac{25}{9\cdot2}=\frac{25}{18}\)
