\(=\dfrac{5}{6}-\dfrac{1}{6}\cdot0,5+2\\ =\dfrac{5}{6}-\dfrac{1}{12}+2\\ =\dfrac{3}{4}+2=\dfrac{11}{4}\)
Lời giải:
\(\sqrt{\frac{25}{36}}-\frac{1}{6}\sqrt{0,25}+\sqrt{(-2)^2}=\sqrt{(\frac{5}{6})^2}-\frac{1}{6}\sqrt{0,5^2}+\sqrt{(-2)^2}\)
\(=|\frac{5}{6}|-\frac{1}{6}|0,5|+|-2|=\frac{5}{6}-\frac{1}{6}.0,5+2=\frac{11}{4}\)
\(\sqrt{\dfrac{25}{36}}-\dfrac{1}{6}\cdot\sqrt{0.25}+\sqrt{\left(-2\right)^2}\)
\(=\dfrac{5}{6}-\dfrac{1}{6}\cdot\dfrac{1}{5}+2\)
\(=\dfrac{25}{30}-\dfrac{1}{30}+\dfrac{60}{30}\)
\(=\dfrac{84}{30}=\dfrac{14}{5}\)
