Question

tính tổng

A=2^0₊2¹+2²⁺2 ²⁰²¹

B=1+3+3²+......+3¹⁰⁰

Answer 1

a: \(2A=2^1+2^2+...+2^{2022}\)

\(\Leftrightarrow A=2^{2022}-1\)

Answer 2

\(A=1+2+2^2+...+2^{2021}\)

\(2A=2+2^2+2^3+...+2^{2020}\)

\(2A-A=\left(2+2^2+2^3+...+2^{2020}\right)-\left(1+2+2^2+...+2^{2021}\right)\)

\(A=2^{2020}-1\)