Question

Tính tổng các đơn thức sau:
\(\dfrac{3}{4}\)xyz²+\(\dfrac{1}{2}\)xyz²+\(\dfrac{-1}{4}\)xyz²

Answer 1

\(\dfrac{3}{4}xyz^2+\dfrac{1}{2}xyz^2+\dfrac{-1}{4}xyz^2=\dfrac{3}{4}xyz^2+\dfrac{2}{4}xyz^2-\dfrac{1}{4}xyz^2=xyz^2\)

Answer 2

\(\dfrac{3}{4}xyz^2+\dfrac{1}{2}xyz^2+\dfrac{-1}{4}xyz^2=xyz^2\)

Answer 3

\(\dfrac{3}{4}xyz^2+\dfrac{1}{2}xyz^2+\dfrac{-1}{4}xyz^2\)

= \(\left(\dfrac{3}{4}+\dfrac{1}{2}+\dfrac{-1}{4}\right)xyz^2\)

= xyz²

Answer 4

   3/4 xyz² + 1/2 xyz² + (-1/4) xyz²

= ( 3/4 + 1/2 - 1/4 ) xyz²

= xyz²

HOK TỐT!