a: \(4\cdot5=2\cdot10\)
=>\(\dfrac{4}{2}=\dfrac{10}{5};\dfrac{4}{10}=\dfrac{2}{5};\dfrac{2}{4}=\dfrac{5}{10};\dfrac{10}{4}=\dfrac{5}{2}\)
b: \(6\cdot63=9\cdot42\)
=>\(\dfrac{6}{9}=\dfrac{42}{63};\dfrac{6}{42}=\dfrac{9}{63};\dfrac{9}{6}=\dfrac{63}{42};\dfrac{42}{6}=\dfrac{93}{9}\)
c: \(14\cdot15=10\cdot21\)
=>\(\dfrac{14}{10}=\dfrac{21}{15};\dfrac{14}{21}=\dfrac{10}{15};\dfrac{10}{14}=\dfrac{15}{21};\dfrac{21}{14}=\dfrac{15}{10}\)
d: ab=cd
=>\(\dfrac{a}{c}=\dfrac{d}{b};\dfrac{a}{d}=\dfrac{c}{b};\dfrac{c}{a}=\dfrac{b}{d};\dfrac{d}{a}=\dfrac{b}{c}\)