Question

tính số mol của:
a) 336ml khí CO₂ ở đktc.
b) 9.10²³ nguyên tử Fe.
c) 6.19g H₂SO₄.

Answer 1

a) \(336\left(ml\right)=0,336\left(l\right)\)

\(n_{CO_2}=\dfrac{V_{CO_2\left(đktc\right)}}{22,4}=\dfrac{0,336}{22,4}=0,015\left(mol\right)\)

Mấy câu sau tương tự nha

Answer 2

b) \(n_{Fe}=\dfrac{9.10^{23}}{6.10^{23}}=1,5\left(mol\right)\)

c) \(M_{H_2SO_4}=1.2+32+16.4=98\left(\dfrac{g}{mol}\right)\)

\(n_{H_2SO_4}=\dfrac{m}{M}=\dfrac{6,19}{98}=\dfrac{619}{9800}\left(mol\right)\)