\(\dfrac{4}{3}-\left[\left(-\dfrac{11}{6}\right)-\left(\dfrac{2}{9}+\dfrac{5}{3}\right)\right]\)
\(=\dfrac{4}{3}+\dfrac{11}{6}+\dfrac{2}{9}+\dfrac{5}{3}\)
\(=3+\dfrac{11}{6}+\dfrac{2}{9}=3+\dfrac{33}{18}+\dfrac{4}{18}=3+\dfrac{37}{18}=\dfrac{54+37}{18}=\dfrac{91}{18}\)