a) `38xx7+7xx62-100xx5`
`= 7(38+62)-500`
`= 7.100-500`
`= 700-500`
`= 200`
b) `(16xx6+16xx3+16)-(12xx6+12xx3+12)`
`= [16(6+3+1)]-[12(6+3+1)]`
`= 16xx10-12xx10`
`= 10(16-12)`
`= 10xx4`
`= 40`
a: \(=7\cdot100-100\cdot5=200\)
b: \(=\dfrac{16\left(6+3+1\right)}{12\left(6+3+1\right)}=\dfrac{16}{12}=\dfrac{4}{3}\)