\(\dfrac{399\times45+399\times55}{1995\times1996-1991\times1995}\\ =\dfrac{399\times\left(45+55\right)}{1995\times\left(1996-1991\right)}\\ =\dfrac{399\times100}{1995\times5}\\ =\dfrac{399\times20}{1995}\\ =\dfrac{1995}{1995}\\ =1\)
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