Question

Tính M = \(\frac{b}{bc+b+1}\)+ \(\frac{a}{ab+a+2}\)+ \(\frac{2c}{ac+2c+2}\)

Biết abc =2

Answer 1

\(M=\frac{b}{bc+b+1}+\frac{a}{ab+a+2}+\frac{2c}{ac+2c+2}\)

\(=\frac{b}{bc+b+1}+\frac{a}{ab+a+abc}+\frac{abc^2}{ac+abc^2+abc}\)

\(=\frac{b}{bc+b+1}+\frac{a}{a\left(bc+b+1\right)}+\frac{abc^2}{ac\left(bc+b+1\right)}\)

\(=\frac{b}{bc+b+1}+\frac{1}{bc+b+1}+\frac{bc}{bc+b+1}\)

\(=\frac{bc+b+1}{bc+b+1}=1\)

Vậy M = 1

Answer 2

= 1 nha

Answer 3

ĐA = 1 nhé.

Nhớ k cho mình nha bạn.

Answer 4

M = 1 nha!

 Nhớ ủng hộ

Answer 5

M = 1 bạn nhé

Answer 6

Online Math là nhất

em yêu Online Math