cái dấu gạch ngang dài bên trên là chỉ phân số nhé
a) \(\frac{2^{10}\times13+2^{10}\times65}{2^8\times104}=\frac{2^{10}\times\left(13+65\right)}{2^8\times104}=\frac{2^{10}\times78}{2^8\times104}=\frac{2^8\times312}{2^8\times104}=\frac{312}{104}=3\)
b) \(\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times\left(65\times111-13\times15\times37\right)\)
\(=\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times\left(65\times111-13\times5\times3\times37\right)\)
\(=\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times\left(65\times111-65\times111\right)\)
\(=\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times0\)
\(=0\)
_Chúc bạn học tốt_
\(\frac{2^{10}.78}{2^8.2^2.26}\)
=\(\frac{2^{10}.78}{2^{10}.26}\)
=\(\frac{78}{26}\)
=3
a) \(\frac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}\)
\(=\frac{2^{10}\cdot\left(13+65\right)}{2^8\cdot104}\)
\(=\frac{2^{10}\cdot78}{2^8\cdot104}\)
\(=\frac{39}{13}\)
\(=3\)
b) \(\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot\left(65\cdot111-13\cdot15\cdot37\right)\)
\(=\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot\left(13\cdot5\cdot111-13\cdot15\cdot27\right)\)
\(=\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot\left(13\cdot555-13\cdot555\right)\)
\(=\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot0\)
\(=0\)
đó là phần a còn phần b là:
(1+2+3+......+100).(12+22+32+.....+102).(195.37-195.37)
=(1+2+3+......+100).(12+22+32+.....+102).0
0
