ta có
E=c-(a+b-d)+a+(a-b)
=c - a -b +d +a +a -b
=(-a +a +a) -(b +b) +c +d
=a - 2b +c +d
thay a=-1 1/3 , b=3 1/2 , c=-5/3 và d=5/12 vào biểu thức trên, ta có
E= \(-1\dfrac{1}{3}-2.(3\dfrac{1}{2})+(\dfrac{-5}{3}+\dfrac{5}{12}\))
E=-4/3 - 2. 7/2 + -5/4
E=-4/3 - 7 - 5/4
E= -115/12
Vậy -115/12 là giá trị của biểu thức E
\(C=c-a-b+d+a+a-b=a-2b+c+d\)
\(=-\dfrac{4}{3}-2\cdot\dfrac{7}{2}+\dfrac{-5}{3}+\dfrac{5}{12}=-3-7+\dfrac{5}{12}\)
=-10+5/12=-115/12
\(E=c-\left(a+b-d\right)+a+\left(a-b\right)\)
\(E=\dfrac{-5}{3}-\left(-1\dfrac{1}{3}+3\dfrac{1}{2}-\dfrac{5}{12}\right)+\dfrac{-5}{3}+\left(\dfrac{-5}{3}-3\dfrac{1}{2}\right)\)
\(E=\dfrac{-5}{3}-\left(-\dfrac{4}{3}+\dfrac{7}{2}-\dfrac{5}{12}\right)+\dfrac{-5}{3}+\left(\dfrac{-5}{3}-\dfrac{7}{2}\right)\)
\(E=\dfrac{-5}{3}-\dfrac{7}{4}+\dfrac{-5}{3}+\left(-\dfrac{31}{6}\right)\)
\(E=-\dfrac{20}{12}-\dfrac{21}{12}-\dfrac{20}{12}-\dfrac{62}{12}\)
\(E=\)\(\dfrac{-20-21-20-62}{12}\)
\(E=-\dfrac{123}{12}=-\dfrac{41}{4}\)
