\(\left(\sqrt{7}+\sqrt{5}\right)\cdot\left(\sqrt{7}+\sqrt{5}\right)\)
\(=\left(\sqrt{7}+\sqrt{5}\right)^2\)
\(=7+2\sqrt{35}+5\)
\(=12+2\sqrt{35}\)
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\(\left(\sqrt{7}+\sqrt{5}\right)\left(\sqrt{7}+\sqrt{5}\right)\)
\(=\left(\sqrt{7}+\sqrt{5}\right)^2\)
\(=12+2\sqrt{35}\)
Đúng 0
Bình luận (0)