\(A=\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+...+\dfrac{2}{192}\)
=>\(2A=\dfrac{4}{3}+\dfrac{2}{3}+\dfrac{2}{6}+...+\dfrac{2}{96}\)
=>\(2A-A=\dfrac{4}{3}-\dfrac{2}{192}\)
=>A=4/3-1/96=127/96
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