\(\dfrac{14}{9}-\dfrac{1}{6}-\dfrac{1}{3}-\dfrac{1}{2}+\dfrac{4}{9}\\ =\left(\dfrac{14}{9}+\dfrac{4}{9}\right)-\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)\\ =\dfrac{18}{9}-\left(\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}\right)\\ =2-\dfrac{6}{6}\\ =2-1\\ =1\)