Tính bằng cách hợp lí:
e, \(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\)
f, \(\dfrac{15^3+5\cdot15^2-5^3}{18^3+6\cdot18^2-6^3}\)
g, \(\left|97\dfrac{2}{3}-125\dfrac{3}{5}\right|+97\dfrac{2}{5}-125\dfrac{1}{3}\)
h, \(\left(\dfrac{-3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)
e: \(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^8}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}=\dfrac{5}{2}\)
f: \(=\dfrac{5^3\cdot3^3+5^3\cdot3^2-5^3}{6^3\cdot3^3+6^3\cdot3^2-6^3}=\dfrac{5^3}{6^3}=\dfrac{125}{216}\)
g: \(=125+\dfrac{3}{5}-97-\dfrac{2}{3}+97+\dfrac{2}{5}-125-\dfrac{1}{3}=0\)
h: \(=\dfrac{7}{3}\left(\dfrac{-3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)=0\)
