Tính bằng cách hợp lí:
a,\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
b,\(1\dfrac{5}{13}-0,\left(3\right)-\left(1\dfrac{4}{9}+\dfrac{18}{13}-\dfrac{1}{3}\right)\)
c, \(139\dfrac{5}{7}:\dfrac{2}{3}-138\dfrac{2}{7}:\sqrt{\dfrac{4}{9}}\)
d, \(\left(-\dfrac{5}{11}:\dfrac{13}{8}-\dfrac{5}{11}:\dfrac{13}{5}\right)+\dfrac{-1}{33}\)
a: \(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}=\dfrac{1}{3}\)
b: \(=1+\dfrac{5}{13}-\dfrac{1}{3}-1-\dfrac{4}{9}+\dfrac{18}{13}+\dfrac{1}{3}=-\dfrac{4}{9}+1=\dfrac{5}{9}\)
c: \(=\dfrac{3}{2}\left(139+\dfrac{5}{7}-138-\dfrac{2}{7}\right)=\dfrac{3}{2}\cdot\left(1+\dfrac{3}{7}\right)\)
\(=\dfrac{3}{2}\cdot\dfrac{10}{7}=\dfrac{15}{7}\)
d: \(=-\dfrac{5}{11}\left(\dfrac{8}{13}+\dfrac{5}{13}\right)+\dfrac{-1}{33}=\dfrac{-5}{11}-\dfrac{1}{33}=-\dfrac{16}{33}\)
