Question

Tính: -2^2+2.(-2/3)+5\(\dfrac{1}{3}\)

Answer 1

\(-2^2+2.\left(-\dfrac{2}{3}\right)+5\dfrac{1}{3}\)

= \(-4+\dfrac{-4}{3}+5+\dfrac{1}{3}\)

= \(-4+\left(-1\right)+5\)

= 0

Answer 2

Ta có: \(-2^2+2\cdot\left(\dfrac{-2}{3}\right)+5\dfrac{1}{3}\)

\(=-4+\dfrac{-4}{3}+\dfrac{16}{3}\)

\(=-4+4\)

=0