Các câu hỏi tương tự
25 tháng 2 2023 lúc 14:53
Bài `1`: Rút gọn các biểu thức sau:a)4x^2left(5x^2+3right)-6xleft(3x^3-2x+1right)-5x^3left(2x-1right)b)dfrac{3}{2}xleft(x^2-dfrac{2}{3}x+2right)-dfrac{5}{3}x^2left(x+dfrac{6}{5}right)Bài `2`: Thực hiện các phép nhân sau:a)left(x^2-xright)cdotleft(2x^2-x-10right)b)left(0,2x^2-3xright)cdot5left(x^2-7x+3right)c)6x^2cdotleft(2x^3-3x^2+5x-4right)d)left(-1,2x^2right)cdotleft(2,5x^4-2x^3+x^2-1,5right)
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Bài `1`: Rút gọn các biểu thức sau:
\(a)4x^2\left(5x^2+3\right)-6x\left(3x^3-2x+1\right)-5x^3\left(2x-1\right)\)
\(b)\dfrac{3}{2}x\left(x^2-\dfrac{2}{3}x+2\right)-\dfrac{5}{3}x^2\left(x+\dfrac{6}{5}\right)\)
Bài `2`: Thực hiện các phép nhân sau:
\(a)\left(x^2-x\right)\cdot\left(2x^2-x-10\right)\)
\(b)\left(0,2x^2-3x\right)\cdot5\left(x^2-7x+3\right)\)
\(c)6x^2\cdot\left(2x^3-3x^2+5x-4\right)\)
\(d)\left(-1,2x^2\right)\cdot\left(2,5x^4-2x^3+x^2-1,5\right)\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
Tìm x :
1) \(\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}\)
2) \(\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0\)
3) \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
4)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
Cho 2 đa thức: \(N\left(x\right)=-4x^4+9x^3-x^2+5x+\dfrac{1}{3}\)
\(M\left(x\right)=-x^4-9x^3+x^2+9x+\dfrac{4}{3}\)
a) Tính \(N\left(x\right)-M\left(x\right)\)
b) Tính \(M\left(x\right)+N\left(x\right)\)
Cho đa thức: P(x) = \(-5^3\) - \(\dfrac{1}{3}\) + \(8x^4+x^2\) và \(Q\left(x\right)\) = \(x^2-5x-2x^3+x^4-\dfrac{2}{3}\).
Hãy tính \(P\left(x\right)+Q\left(x\right)\) và \(P\left(x\right)-Q\left(x\right)\)
Bài 1: Tính một cách hợp líd) (^{2^2} : dfrac{4}{3} - ^{dfrac{1}{2}} ) x dfrac{6}{5} - 17h) dfrac{left(-1right)^3}{15} + left(-dfrac{2}{3}right)^2 : 2dfrac{2}{3} - left|-dfrac{5}{6}right|k) dfrac{2.6^9-2^5.18^4}{2^2.6^8}n) 3 - left(-dfrac{7}{8}right)^0 + left(dfrac{1}{2}right)^3 . 16Mg giải gấp giúp mình ạ
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Bài 1: Tính một cách hợp lí
d) (\(^{2^2}\) : \(\dfrac{4}{3}\) - \(^{\dfrac{1}{2}}\) ) x \(\dfrac{6}{5}\) - 17
h) \(\dfrac{\left(-1\right)^3}{15}\) + \(\left(-\dfrac{2}{3}\right)^2\) : \(2\dfrac{2}{3}\) - \(\left|-\dfrac{5}{6}\right|\)
k) \(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}\)
n) 3 - \(\left(-\dfrac{7}{8}\right)^0\) + \(\left(\dfrac{1}{2}\right)^3\) . 16
Mg giải gấp giúp mình ạ
Tìm x a,3-xx+1,8b,2x-57x+35c,2left(x+10right)3left(x-6right)d,8left(x-dfrac{3}{8}right)+16left(dfrac{1}{6}+xright)+xe,dfrac{2}{9}-3xdfrac{4}{3}-xg,dfrac{1}{2}x+dfrac{5}{6}dfrac{3}{4}x-dfrac{1}{2}h,x-4dfrac{5}{6}left(6-dfrac{6}{5}xright)k,7x^2-116x^2-2m,5left(x+3.2^3right)10^2n,dfrac{4}{9}-(dfrac{1}{6^2})dfrac{2}{3}left(x-dfrac{2}{3}right)^2+dfrac{5}{12}
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Tìm x
\(a,3-x=x+1,8\)
\(b,2x-5=7x+35\)
\(c,2\left(x+10\right)=3\left(x-6\right)\)
\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)
\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)
\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)
\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)
\(k,7x^2-11=6x^2-2\)
\(m,5\left(x+3.2^3\right)=10^2\)
\(n,\dfrac{4}{9}-(\dfrac{1}{6^2})=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)
\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(\left(\dfrac{15}{4}-5x\right)\cdot\left(9x^2-4\right)=0\)
\(\sqrt{x-2}+\dfrac{1}{3}=1\)
Tìm x, biết:
a) \(-\dfrac{2}{3}\left(x+1\right)=\dfrac{1}{6}-x\)
b) \(3\left(x+\dfrac{1}{3}\right)-\dfrac{1}{2}\left(x+2\right)=\dfrac{5}{2}x-1\)
\(\left(\dfrac{-2}{3}\right)^2.x=\left(\dfrac{-2}{3}\right)^5\)
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)
\(\left(\dfrac{2}{3}x-1\right)\left(\dfrac{3}{4}x+\dfrac{1}{2}\right)=0\)
\(\dfrac{4}{9}:x=3\dfrac{1}{3}:2,25\)
\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:0,1x\)