Bài 1:
=>y-69,3=20,5
hay y=89,8
Bài 2:
a: \(=365.4:43.5-7.7\cdot0.2\)
=8,4-1,54=6,86
b: \(=\dfrac{2}{5}:\dfrac{8-5}{10}+\dfrac{3}{5}=\dfrac{2}{5}\cdot\dfrac{10}{3}+\dfrac{3}{5}=\dfrac{20+9}{15}=\dfrac{29}{15}\)
Bài 1:
=>y-69,3=20,5
hay y=89,8
Bài 2:
a: \(=365.4:43.5-7.7\cdot0.2\)
=8,4-1,54=6,86
b: \(=\dfrac{2}{5}:\dfrac{8-5}{10}+\dfrac{3}{5}=\dfrac{2}{5}\cdot\dfrac{10}{3}+\dfrac{3}{5}=\dfrac{20+9}{15}=\dfrac{29}{15}\)
( 1 - \(\dfrac{1}{2}\) ) ✖ ( 1 - \(\dfrac{1}{3}\) ) ✖ ( 1 - \(\dfrac{1}{4}\) ) ✖ ( 1 - \(\dfrac{1}{5}\) ) ✖ ( 1 - \(\dfrac{1}{6}\) ) ✖ ( 1 - \(\dfrac{1}{7}\) ) ✖ (1 - \(\dfrac{1}{8}\))
Tìm y
y ✖ 2 + y ✖ \(\dfrac{1}{5}\) = \(1\dfrac{3}{5}\) giúp mik với mik cần rất chi là gấp
Bài 2: (đề 2) Tìm y
a) \(2\dfrac{2}{5}-y:2\dfrac{3}{4}=1\dfrac{1}{2}\) b) \(1\dfrac{1}{4}+2\dfrac{1}{5}\) x \(y=2\dfrac{3}{5}\)
c) \(2\dfrac{4}{5}-2\dfrac{1}{4}:y=\dfrac{3}{4}\) c) \(x:3\dfrac{1}{3}=2\dfrac{2}{5}+\dfrac{7}{10}\)
Sos mn ơi
Tìm Y
\(\dfrac{11}{4}-y-\dfrac{2}{5}=\dfrac{1}{3}\). \(\dfrac{5}{3}x\left(\dfrac{3}{4}-y:\dfrac{2}{5}\right)=\dfrac{5}{8}\)
\(\dfrac{3}{2}xy-\dfrac{3}{4}xy+y=\dfrac{4}{5}\)
Bài 3: (Đề 2) Tìm y
a) \(2\dfrac{2}{5}:\) y x \(1\dfrac{3}{4}=\dfrac{7}{8}\) b)\(3\dfrac{2}{5}:y:1\dfrac{1}{4}=2\dfrac{3}{5}\) c) \(\dfrac{12}{5}-2\dfrac{2}{5}x\) y \(=1\dfrac{1}{4}\)
Tìm y
\(\dfrac{2}{5}\) X y : \(\dfrac{7}{4}=\dfrac{7}{8}\)
2\(\dfrac{2}{5}\) : y x 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\)
\(\dfrac{12}{5}-1\dfrac{2}{5}x\) y = 1\(\dfrac{1}{4}\)
bài 3: Tìm y
a) \(\dfrac{1}{2}\) : y x \(\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\) b) \(\dfrac{4}{3}-\dfrac{1}{2}\) x y \(=1\) c) \(\dfrac{1}{4}+y\) : \(\dfrac{1}{3}=\dfrac{5}{6}\)
bài 3: Tính
a) \(\dfrac{4}{5}x\dfrac{5}{8}:\dfrac{4}{5}\)
b) \(\dfrac{5}{6}+\left(\dfrac{1}{2}:\dfrac{3}{2}+\dfrac{4}{5}\right)\)
bài 4 Tìm y
\(\dfrac{3}{4}+y:\dfrac{2}{5}=\dfrac{37}{16}\) 456 + y : 87 = 23987
tính giá trị của biểu thức
\(\dfrac{5}{8}:\dfrac{3}{4}_{ }-\dfrac{1}{6}\) \(\left(\dfrac{3}{14}+\dfrac{1}{2}\right)X\dfrac{7}{5}\)