\(x^2+y^2+4z^2+2x+2y+4z+3=0\)
\(\Leftrightarrow\)\(\left(x^2+2x+1\right)+\left(y^2+2y+1\right)+\left(4z^2+4z+1\right)=0\)
\(\Leftrightarrow\)\(\left(x+1\right)^2+\left(y+1\right)^2+\left(2z+1\right)^2=0\)
\(\Leftrightarrow\)\(\hept{\begin{cases}x+1=0\\y+1=0\\2z+1=0\end{cases}}\)\(\Leftrightarrow\)\(\hept{\begin{cases}x=-1\\y=-1\\z=-\frac{1}{2}\end{cases}}\)
Vậy....
x^4-y^4+z^4+2x^2y^z+3x^2+4z^2+1=0 tìm x,y thuộc z
Tìm x,y,z biết: a) x^2+y^2-4x+4y+8=0 b) 5x^2-4xy+y^2=0 c) x^2+2y^2+z^2-2xy-2y-4z+5=0 d) 3x^2+3y^2+3xy-3x+3y+3=0 e) 2x^2+y^2+2z^2-2xy-2xz+2yz-2z-2z-2x+2=0
tìm x,y biết:
1) 5x2 + 3y2 + z2 - 4z + 6xy + 4z + 6 = 0
2) 2x2 + 2y2 + z2 + 2xy + 2xz + 2x + 4y + 5 = 0
3) 2x2 + 2y2 + z2 + 2xy +2xz + 2yz + 10x + 6y + 34 = 0
Tìm x, y, z biết rằng: x^2 + 2x + y^2 – 6y + 4z^2 – 4z + 11 = 0
tìm x,y,z thỏa mãn đẳng thức x^2-2x+y^2+4y+4z^2-4z+6=0
Tìm x,y,z biết x2+2x+y2-6y+4z^2-4z+11=0
Tìm x,y,z biết \(x^2+2y^2+3z^2+2xy+2yz+2zx+2y+4z+3=0\)=0
tìm x,y,z biết:
x2+2x+y2-6x+4z2-4z+11=0
Tìm x, y,z: \(x^2+y^2+3z^2+2xy+2yz+2zx+2y+4z+3=0\)
