Question

tìm x,y,x 

Answer 1

Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{2}=\dfrac{y-x}{7-5}=\dfrac{48}{2}=24\)

\(\dfrac{x}{5}=24\Rightarrow x=120\\ \dfrac{y}{7}=24\Rightarrow y=168\\ \dfrac{z}{2}=24\Rightarrow z=48\)

Answer 2

Áp Dụng tích chất dãy tỉ số bằng nhau ta có:

\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{2}=\dfrac{y-x}{7-5}=\dfrac{48}{2}=24\)

Do đó: \(\dfrac{x}{5}=24\Rightarrow x=5.24=120\)

\(\dfrac{y}{7}=24\Rightarrow7.24=168\)

\(\dfrac{z}{2}=24\Rightarrow2.24=48\)

Vậy........