Question

tìm x

(x+1)=(x+1)^2

 

Answer 1

(x+1)=(x+1)^2

(x+1)-(x+1)^2=0

(x+1)(1-x-1)=0

-x(x+1)=0

có 2 giá tri x

x=-1

x=0

Answer 2

(x + 1) = (x + 1)² 

(x + 1) . 1 = (x + 1)(x + 1) 

=> x + 1 = 1 

=> x = 0